Cos(4x)+2cos^2(x)=1

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Solution for Cos(4x)+2cos^2(x)=1 equation:


Simplifying
Cos(4x) + 2cos2(x) = 1

Remove parenthesis around (4x)
osC * 4x + 2cos2(x) = 1

Reorder the terms for easier multiplication:
4osC * x + 2cos2(x) = 1

Multiply osC * x
4osxC + 2cos2(x) = 1

Multiply cos2 * x
4osxC + 2cos2x = 1

Reorder the terms:
2cos2x + 4osxC = 1

Solving
2cos2x + 4osxC = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4osxC' to each side of the equation.
2cos2x + 4osxC + -4osxC = 1 + -4osxC

Combine like terms: 4osxC + -4osxC = 0
2cos2x + 0 = 1 + -4osxC
2cos2x = 1 + -4osxC

Divide each side by '2os2x'.
c = 0.5o-1s-2x-1 + -2s-1C

Simplifying
c = 0.5o-1s-2x-1 + -2s-1C

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